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# Thread: Brass Chandioler meets a 25' drop!

1. I dont believe its possble for that to occur in the first second of freefall. it would have to be less than 32 ft/sec.

2. ## For pete's sakes...

All the calculations, speculations and inquires regarding this lamp brought me back to that night and if I can just add on last thing. In the unfortunate event someone had been under that lamp when it fell, they could give a Hamster's as! about the math.

Just fun guy's

TacMig
Last edited by tacmig; 10-25-2007 at 07:51 PM.

3. I had to correct my errors. My original problem, I used 9.8 for acceleration. 9.8 meters/sec is correct, but since we're using feet, this needed to change to 32 ft/sec. Also, had to correct the formula. We don't use Vo^2 (v naught squared). I guess my memory is not so good from high school physics in 1982...

Here is a good reference I found on the internet.
http://mathforum.org/library/drmath/view/56288.html

Originally Posted by crawler

**** Below is the correct version ****

<<<Use this formula to determine how long it will take an object to fall to the ground.>>

s= Vo (v naught) + 1/2 at^2 (at squared)

Where
s= distance
Vo = initial velocity
a= acceleration, 32 feet per second
t2= time squared

25 feet = 0 + 1/2(32) t2
25 = 1/2 x 32t2
25= 16t2
1.5625=t2
1.25=t

It takes 1.25 seconds for the chandelier to fall 25 feet.

======================================

<<To calculate terminal speed when it hit the floor:>>

where
v= velocity
Vo= initial velocity
a= acceleration (32 ft/sec)
t=time

v=Vo + at
v=0 + 32(1.25)
v=40

Velocity of chandelier hitting the floor is 40 feet/second.
Last edited by crawler; 10-25-2007 at 08:12 PM.

4. Originally Posted by crawler
I had to correct my errors. My original problem, I used 9.8 for acceleration. 9.8 meters/sec is correct, but since we're using feet, this needed to change to 32 ft/sec. Also, had to correct the formula. We don't use Vo^2 (v naught squared). I guess my memory is not so good from high school physics in 1982...

Here is a good reference I found on the internet.
http://mathforum.org/library/drmath/view/56288.html
hehehehe, I kneew that! I was just seeing if you knew!!

something didnt seem right about the distance to the floor, but hey, that sure was some tasty deer!!!

5. Senior Member
Join Date
Aug 2007
Location
Honolulu, HI
Posts
103
I'm just amazed that someone took the trouble to calculate it!

6. Senior Member
Join Date
Jun 2006
Location
Killingworth,Ct.
Posts
372

## So

If it was going 10,000 ft per second,it still has to be repaired!!!!!!,,I agree with Johnny Mag!!!!!!my 2 cents,Jack

7. Originally Posted by storts
If it was going 10,000 ft per second,it still has to be repaired!!!!!!,,I agree with Johnny Mag!!!!!!my 2 cents,Jack
My exact thoughts!

Who cares how fast it was going, and who cares how hard it hit. I'm just glad it fell so we can watch Bob do some mighty fine repairs on it. Dave

8. Originally Posted by dabar39
My exact thoughts!

Who cares how fast it was going, and who cares how hard it hit. I'm just glad it fell so we can watch Bob do some mighty fine repairs on it. Dave
Well Bob,
Hows it going? are you making any headway? Is it..."falling into place" as it should ? Is it going as "fast" as it should? hehehehe..

I am told it is better to be a smart as\$ rather than a dumbAs\$...

9. Its going great. Got the big dent out of the big 12" brass ball, just need to weld a small crack and little dent and repolish. I used to help a guy polish those big old phonograph brass horns 500 at a time so i know how to polish and have the equipment. Cut some new tabs from brass plate to braze on to the arms but i need to make 2 fixtures to hold them right then make a new rod to hold everything straight because the old one is bent...Bob

10. Pics since i forgot them...Bob

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